InterviewSolution
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InterviewSolution
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A reaction is first order in A and second order in B. (i) Write the differential rate equation. (ii) How is rate affected on increasing the concentration of B three times ? (iii) How is rate affected when the concentration of both A and B are doubled ? |
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Answer» Solution :(i) rate ` = - (DX)/(DT) = k[A]^(1) [B]^(2)` (ii)rate ` = k[A]^(!) [3B]^(2) = 9k[A]^(1) [B]^(2)`. Rate increases by 9 TIMES. (iii) `r = k[2A]^(1) [2B]^(2) = 8K [A}^(1) [B]^(2)` . Rate increases by 8 times. |
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