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A reaction is of second order in A and first order in B. How is the rate affected when the concentration of both A and B is doubled ? |
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Answer» SOLUTION :A reaction is SECOND order in A and first order in B When concentration of both A and B is doubled then, Rate `= k[2A]^(2)[2B]=8k [A]^(2)[B]=8` (INITIAL rate) This shows that rate will increase 8 times to the initial rate. |
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