1.

A reaction is of second order in A and first order in B. How is the rate affected when the concentration of both A and B is doubled ?

Answer»

SOLUTION :A reaction is SECOND order in A and first order in B
When concentration of both A and B is doubled then,
Rate `= k[2A]^(2)[2B]=8k [A]^(2)[B]=8` (INITIAL rate)
This shows that rate will increase 8 times to the initial rate.


Discussion

No Comment Found