1.

A reaction rate constant is given by k = 1.2 xx 10^(14) e^(-(25000//RT)) sec^(-1) . It means

Answer»

log k versus log T will GIVE a straight line with slope as `- 25000`
log k versus T will give a straight line with slope as `- 25000`
log k versus log 1/T will give a straight line with slope `-25000`
log k versus 1/T will give a straight line

Solution :ACCORDING to the Arrhenius equation a straight line is to be obtained by plotting the logarithm of the rate CONSTANT of a chemical reaction (log k) against 1/T.


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