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InterviewSolution
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A reactions is of second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is reduced to half? |
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Answer» According to given information Rate = K `["Reactant"]^(2)` If concentration of reactant becomes twice . (i) `(R_("new"))/(R_("old")) = ([2R]^(2))/([R]^(2)) = 4` times increases . If concentration of reactant becomes half . (ii) `(R_("new"))/(R_("old")) = [(R)/(2R)]^(2) = (1)/(4)` times increases. |
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