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A reactor is supplied with 5 moles each of CH3OH and O2, and the following reactions occur, CH3OH + 1/2O2 -> CH2O + H2O and then CH2O + 1/2O2 -> CO + H2O, the conversion of methanol is 80% in first reaction, and conversion of CH2O is 50% in second reaction. How many moles of O2 are there in the products?(a) 1.75(b) 2(c) 3.25(d) 5.5This question was posed to me in an international level competition.Enquiry is from Processes Involving Multiple Units in division The Chemical Reaction Equation & Stoichometry, Material Balances for Processes Involving Reaction and Multiple Units of Basic Chemical Engineering

Answer»

Correct CHOICE is (a) 1.75

The BEST explanation: EXTENT of REACTION E1 = (-0.8)/(-1) = 0.8, E2 = (-0.5)/(-1) = 0.5, => moles of O2 = (2.5 – 2.5*0.8) + (2.5 – 2.5*0.5) = 1.75.



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