InterviewSolution
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A rectangle has twice the area of a square. The length of the rectangle is 12 cm greaterd the perimeter of theand the width is 8 cm greater than a side of a square. Find perimeter of square. |
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Answer» let the side of square is a , so area = a². then area of rectangle is l*b = (a+12)(a+8) = a²+20a+96 . but rectangular area is 2 times the square .so,2a² = a² +20a +96 => a²-20a-96 = 0=> a²-24a+4a -96 = 0=> a(a-24)+4(a-24) = 0=> (a-24)(a+4) = 0 so, a = 24cm now perimeter is 4*a = 24*4 = 96cm. khud sa bhibkabhi bana liyaa karo humesa google ma sahayata mat karob let one side of the square be x then length of rectangle = 12+xand breadth = 8+xarea of sqaure = x²area of rectangle = l*b →(12+x)(8+x) given - ar( rectangle )=2* ar(square) (12+x)(8+x)=2x²96+20x +x²= 2x²x²-20x-96=0x²-24x+4x-96=0x(x-24)+4(x-24)=0(x-24)(x+4)=0x=24 ( neglecting x=-4 since lenght cannot be negative) lenght of rect- 36breadth - 32 perimeter - 2*(32+36)= 136units kabhi apna bhi brain use kar liyaa karo bewkoofo |
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