A rectangle is (8x + 5) cm long and (5x + 3) cm broad. Find its area.

1.	A rectangle is (8x + 5) cm long and (5x + 3) cm broad. Find its area.
Answer» Length of the rectangle = (8x + 5) cm Breadth of the rectangle = (5x + 3) cm ∴ Area of the rectangle = length × breadth = (8x + 5) × (5x + 3) = 8x × (5x + 3) + 5 × (5x + 3) = (8x × 5x) + (8x × 3) + (5 × 5x) + (5 × 3) = 40x² + 24x + 25x + 15 = 40x² + 49x + 15 ∴ The area of the rectangle is (40x² + 49x + 15) sq. cm.

Answer»

Length of the rectangle = (8x + 5) cm

Breadth of the rectangle = (5x + 3) cm

∴ Area of the rectangle = length × breadth

= (8x + 5) × (5x + 3)

= 8x × (5x + 3) + 5 × (5x + 3)

= (8x × 5x) + (8x × 3) + (5 × 5x) + (5 × 3)

= 40x² + 24x + 25x + 15

= 40x² + 49x + 15

∴ The area of the rectangle is (40x² + 49x + 15) sq. cm.

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