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A rectangle is inscribed in a circle with a perimeter lying along the line 3y = x+7. If the two adjacement verticles of the rectangle are (-8, 5) and (6,5), then the area of the rectangle ( in sq units) is |
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Answer» 72 Let `(-8, beta) and (6, beta)` are the coordinates of the other vertices of rectangle as shown in the figure. Since, the mid-point of line JOINING points (-8, 5) and `(6, beta)` lies on the line 2y = x + 7. `therefore 3((5+beta)/(2))=(-8+6)/(2)+7` `rArr 15 + beta=-2+14` `rArr 3beta=-3rArrbeta = -1` Now, area of rectangle `=|-8-6|xx|beta-5|` `=14+6=84` |
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