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A rectangular bar having a cross-sectional area of 80 mm2 has a tensile force of 20 kN applied to it. Determine the stress in the bar. |
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Answer» Stress \(\sigma\) = \(\cfrac{force F}{area A}\) = \(\cfrac{20\times10^3}{80\times10^{-6}}\) = 250 x 106 pa = 250 Mpa |
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