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A rectangular coil of 10 turns, each of area 0.05 m2 , is suspended freely in a radial magnetic field of 0.01 Wb/m2. If the torsional constant of the suspension fibre is 5 × 10-9 N∙m per degree, find the angle through which the coil rotates when a current of 30 μA is passed through it. |
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Answer» Data : A = 0.05 m2, B = 0.01 Wb/m2, N = 10, C = 5 × 10-9 N∙m per degree, I = 30 μA = 30 × 10 A, I = \(\left(\cfrac{C}{NAB}\right)\) θ ∴ The deflection of the coil, θ = \(\cfrac{NIAB}C\) = \(\cfrac{10\times30\times10^{-6}\times0.05\times0.01}{5\times10^{-9}}\) = 30° |
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