InterviewSolution
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InterviewSolution
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A rectangular coil of 100 turns has length 5cm and width 4cm. It is placed with its plane parallel to a uniform magnetic field and a current of 2A is sent through the coil. Find the magnitude of the magnetic field B, if the torque acting on the coil is 0.2N-m. |
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Answer» τ = ni vector A x vector B => τ = ni ABsin90º = => 0.2 = 100 x 2 x 5 x 4 x 10-4 x B => B = 0.2/(100 x 2 x 5 x 4 x 10-4) = 0.5Tesla
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