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A rectangular frame having dimensions of 5 cm xx 3 cm xx 3 mm is placed vertical in such a way that its longest side just touches the water surface. What will be the downward force acting on the frame? Surface tension of water is 0.72 Nm^(-1). |
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Answer» Solution :T=surface tension FORCE `=T XX 2 ("LENGTH+ THICKNESS")` `=0.072 xx 2(5 xx 10^(-2) +3 xx 10^(-3))` `=0.144 (0.05+0.003)` `=0.007 or 7 xx 10^(-3)N` |
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