1.

A rectangular frame of length 20 cm is dipped in a soap solution and then raised, forming a soup film on the frame. The pull required is 2.83 g wt more before the film breaks. Calculate the surface tension of the liquid.

Answer»

SOLUTION :The additional pull of 2.83 g wt is equal to the force of surface tension,
`F= "2.83 g wt= 2.83 "XX "981 dyne"`
As the solution touches the frame both on outside and inside along its length, so force the frame due to surface tension is
`F=2 xx l xx sigma=2l sigma`
`rArr 2.83 xx 981 =2 xx 10 xx sigma`
`rArr sigma=(2.83 xx 981)/(20)="138.8 dyne/cm"`


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