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A rectangular loop has a sliding connector PQ of length l and resistance `R (Omega)` and it is moving with a speed v as shown. The set-up is placed in a uniform magnetic field going into the plane of the paper. The three currents `I_(1), I_(2)` and I are A. `l_(1)=-l_(2)=(Blv)/(R),l=(2Blv)/(R)`B. `l_(1)=l_(2)=(Blv)/(3R),l=(2Blv)/(3R)`C. `l_(1)=l_(2)=l=(Blv)/(R)`D. `l_(1)=l_(2)=(Blv)/(6R),l=(Blv)/(3R)` |
Answer» Correct Answer - B | |