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A rectangular metal ................

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Solution :The COEFFICIENT of VISCOSITY is the ratio of tangential stress on top surface of film (exerted by block) to that of velocity gradient (vertically downwards) of film. Since mass m moves with constant velocity, the string exerts a force EQUAL to mg on plate towards right. Hence oil shall exert tangential force mg on plate towards left.
`:. eta=(F//A)/((v-0)//Delta x)=(125xx1000//10xx20)/((5-0)//.02)=2.5` DYNE - `s//cm^(2)`


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