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A rectangular surface of sides `10 cm and 15 cm` is palaced inside a uniform electric field fo `25 Vm^(-1)`, such that normal to the surface makes an angle of `60^(@)` with the direction of electric field. Find the flux of electric field through the rectangular surface. |
Answer» Correct Answer - `1.8xx10^(-1) Nm^(2) C^(-1)` Here, `E = 25 Vm^(-1)`, `s = 10xx15 cm^(2) = 150xx10^(-4) m^(2)` `theta = 60^(@) , phi = ?` `phi = Es cos theta = 25xx150xx10^(-4) cos 60^(@)` `phi = 1.8xx10^(-1) Nm^(2) C^(-1)` |
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