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A refrigerator having a power rating of 350W operates for 10 hours a day. Calculate the cost of electrical energy to operate if for a month of 30 days. The rate of electrical energy is Rs. 340 per kWh. |
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Answer» Electrical energy, `E = P xx t` Power, `P = 350 W` `= (350)/(1000) kW` `= 0.35 kW` And, Time, `t = 10 xx 30` hours `= 300 h` Now, putting these values of P and t in the formula, `E = P xx t` We get: `E = 0.35 xx 300 kWh` `= 105 kWh` Thus, the electrical energy consumed by the refrigerator in a month of 30 days is 105 kilowatt-hours. Now, Cost of 1 kWh of electricity = Rs. 3.40 So, Cost of 105 kWh of electricity = Rs. `3.40 xx 105` = Rs. 357` |
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