1.

A refrigerator is working between the temperature of melting ice and room temperature, which is 290 K. Calculate work done by the refrigerator to freeze 2 kg of water.

Answer»

SOLUTION :Work done ` = Q _(1) - Q _(2) = (T_(1) - T _(2)) Q _(2) // T _(2) = (290 - 273) xx 2 xx 333 xx 10 ^(3) // 273 = 4.14 xx 10 ^(4) J`


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