1.

A refrigerator whose coefficient of performance is 5 extracts heat from the cooling compartment at the rate of 250 J per cycle. How mush electric energy is spend per cycle ? How much heat per cycle is discharged to the room ?

Answer»

Solution :`beta = (Q_(2))/(W)`
`:. W = (Q_(2))/(beta) = (250)/(5) = 50 J`
`:.` Electric energy SPENT per cycle = 50 J
Again, `Q_(1) = Q_(2) + W`
or `Q_(1) = 250 + 50` or `Q_(1) = 300 J`
`:.` HEAT energy discharged per cycle to room = 300 J


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