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A refrigerator whose coefficient of performance is 5 extract heat from the cooling compartment at the rate of 250J/cycle. How much electric energy is spent per cycle? How much heat per cycle is discharge to the room? |
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Answer» As `C.O.P= (Q_(2))/W` `:. W=(Q_(2))/(C.O.P)= (250)/5= 50J` Heat/ cycle discharge to the room `Q_(1)=Q_(2)+W= 250+50=300J` |
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