A refrigerator, whose coefficient of performance K is 5, extracts heat from the cooling compartment at the rate of 250 J per cycle. a0 How much work per cycle is required to operate the refrigerator cycle? ( b) How much heat per cycle is discharged to the room which acts as the high temperature reservoir?

A refrigerator, whose coefficient of performance K is 5, extracts heat

1.	A refrigerator, whose coefficient of performance K is 5, extracts heat from the cooling compartment at the rate of 250 J per cycle. a0 How much work per cycle is required to operate the refrigerator cycle? ( b) How much heat per cycle is discharged to the room which acts as the high temperature reservoir?
Answer» SOLUTION :a) As coefficient of PERFORMANCE of a refrigerator is DEFINED as `K=Q_(L)//W," So "W=Q_(L)/K=250/5=50J` B)As `Q_(H)=Q_(L)+W" so "Q_(H)=250+50=300J`