A refrigerator works between 4^(@)C and 30^(@)C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerator space constant. The power required is (Takae 1 cal = 4.2 Joules)

A refrigerator works between 4^(@)C and 30^(@)C. It is required to rem

1.	A refrigerator works between 4^(@)C and 30^(@)C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerator space constant. The power required is (Takae 1 cal = 4.2 Joules)
Answer» 236.5 W 2365 W 2.365 W 23.65 W Solution :Given, `T_(2) = 4^(@)C = 277 K, T_(1) = 30^(@)C = 303 K` `Q_(2) = 600` cal per second Coefficient of performance. `alpha = (T_(2))/(T_(1) - T_(2)) = (277)/(303 - 277) = (277)/(26)` Also, `alpha = (Q_(2))/(W)` `:.` Work to be done second = power REQUIRED `= W = (Q_(2))/(alpha) = (26)/(277) xx 600` cal per second `= (26)/(277) xx 600 xx 4.2 J` per second = 236.5 W