A remote - sensing satellite of earth revolves in acircular orbit at a height of 0.25 x 106 m above the surface of earth. It earth's radius is 6.38 xx 10^(6)m and g = 9.8 ms^(- 2) , then the orbital speed of the satellite is ..........

A remote - sensing satellite of earth revolves in acircular orbit at a

1.	A remote - sensing satellite of earth revolves in acircular orbit at a height of 0.25 x 106 m above the surface of earth. It earth's radius is 6.38 xx 10^(6)m and g = 9.8 ms^(- 2) , then the orbital speed of the satellite is ..........
Answer» `6.67 kms^(-1)` `7.76 kms^(-1)` `8.56 kms^(-1)` `9.13 kms^(-1)` Solution :`implies` For SATELLITE revolves around EARTH, `v_0 = SQRT((GM_e)/(Re+h))= sqrt((GMe)/(Re(1+h/(Re))))` `:. v_0 = sqrt((gRe)/(1+h/(Re)))""[ :. GM_e = gR_e^2]` `:. v_0 = sqrt((9.8 xx6.38 xx10^6)/(1+(0.25xx10^6)/(6.38 xx 10^6)))` `:. v_0 = sqrt(62.524 xx10^6)/(1.0392)` `:. v_0 =sqrt(60.16 xx 10^6)` `:. v_0 = 7.7566 xx 10^3 m//s` `:. v_0 ~~ 7.76 kms^(-1)`