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A resistance coil is made by joining in parllel two resistances each of `10 Omega`. An emf of 1.0V is applied between the two ends of the coil for 5 minutes. Calculate the heat produced in calories. (Given 1 cal. = 4.2 J) |
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Answer» Here, `R_(1) = 10 Omega, R_(2)= 10 Omega`, `V = 1.0 V, t = 5 xx 60s` Effective resistance in parallel combination will be `R_(p) = (R_(1) R_(2))/(R_(1) + R_(2)) = ( 10 xx 10)/( 10 +10) = 5 Omega`, Heat produced `= V^(2)/R_(p) t = 1^(2)/5 xx 5 xx 60 J` `= 60/4.2 cal = 14.3` cal. |
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