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A resistance of `1980Omega` is connected in series with a voltmeter, after which the scale division becomes 100 times larger. Find the resistance of voltmeter. |
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Answer» Let R be the resistance of voltmeter. Let n be the number of divisions in the voltmeter. The voltage `(V)` recorded by each division of voltmeter when current `i_g` flows through it is `i_gR//n=V` …(i) When resistance is connected in series with voltmeter, then `i_g(R+1980)//n=100V` ...(ii) Dividing (ii) by (i), we get `R+1980=100R` or `R=1980//99` `=20Omega` |
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