A resistance of 20ohm is connected to a source of an alternating potential v=220sin (100piet). The time taken by the current to change from its peak value to rms value is . a) 0.2sec b)0.25sec c) 2.5×10-33sec

A resistance of 20ohm is connected to a source of an alternating pot

1.	A resistance of 20ohm is connected to a source of an alternating potential v=220sin (100piet). The time taken by the current to change from its peak value to rms value is . a) 0.2sec b)0.25sec c) 2.5×10-33sec
Answer» R = 20 Ω V = 220 sin (100πt) we know that V = V. sin(ωt) I = V. sin(ωt) / R I = 220 sin (100πt) / 20 I = 11 sin (100πt) Also I_rms = I_peak sin (100πt) and I_rms = I_peak / √ 2 I_peak sin (100πt) = I_peak / √ 2 100πt = π / 4 t = 1 / (4x100) t = 1 / 400 t = 0.0025 = 2.5 x 10^-3

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A resistance of 20ohm is connected to a source of an alternating potential v=220sin (100piet). The time taken by the current to change from its peak value to rms value is . a) 0.2sec b)0.25sec c) 2.5×10-33sec

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