1.

A resistance of 3 Ω is connected to the secondary coil of 60 turns of an ideal transformer. Calculate the current (peak value) in the resistor if the primary has 1200 turns and is connected to 240 V (peak) ac supply. Assume that all the magnetic flux in the primary coil passes through the secondary coil and that there are no other losses.

Answer»

Data : R = 3 Ω, Ns = 60, Np = 1200, Vp = 240 V

Vs = \(\cfrac{N_S}{N_P}\) × Vp

\(\cfrac{60}{1200}\) x 240 = 12 V (peak)

∴ The peak value of the current in the resistor in the transformer secondary coil is

Is\(\cfrac{V_S}{R}\) = \(\cfrac{12}{3}\) = 4 A



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