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A resistance of 40 ohms and one of 60 ohms are arranged in series across 220 volt supply. Find the heat in joules produced by this combination of resistances in half a minute. |
Answer» Given R1 = 40 ohms,, R2 = 60 ohms V = 220 V, t = 30sec we know that Total resistance, R = 40 + 60 = 100 ohms By Ohm's law, V = IR I = V/R I = 220/100 = 2.2 amp putting the values of I,R and t in eq. H = I2RT H = 2.22 x 100 x 30 H = 14520 J |
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