A resistance of `50Omega` is registered when two electrodes are suspended into a beaker containing a dilute solution of a strong electrolyte such that exactly half of them are submerged into solution as shown in figure. If the solution is diluted by adding pure water (negligible conductivity) so as to just completely submerge the electrodes, the new ressitance offered by the solution would be: ltbegt A. `50 Omega`B. `100 Omega`C. `25Omega`D. `200Omega`

A resistance of `50Omega` is registered when two electrodes are suspen

1.	A resistance of `50Omega` is registered when two electrodes are suspended into a beaker containing a dilute solution of a strong electrolyte such that exactly half of them are submerged into solution as shown in figure. If the solution is diluted by adding pure water (negligible conductivity) so as to just completely submerge the electrodes, the new ressitance offered by the solution would be: ltbegt A. `50 Omega`B. `100 Omega`C. `25Omega`D. `200Omega`
Answer» Correct Answer - A

Discussion

No Comment Found

Related InterviewSolutions

The EMF of the following cell: `Zn| Zn^(2+)(0.1M) || Cl^(-)(0.01M) | AgCl | Ag` is: [Given : E_(Zn^(2+)|/Zn)^(@) = -0.76V`, `E_(Cl^(-)| AgCl|Ag)^(@)` = 0.22 V`, `(2.303RT)/(F) = 0.06]`A. 0.96 VB. 0.345 VC. 1.23D. 1.13 V
`DeltaG^(@)` of the cell reaction `AgCl(s) + 1/2H_(2) rightarrow Ag(s) + H^(+) + Cl^(-)` is `-21.52kJ`. `DeltaG^(@)` of 2AgCl(s) + H_(2)(g) rightarrow + 2H^(+) + 2Cl^(-)` isA. `-21.52kJ`B. `-10.76 kJ`C. `-43.04kJ`D. `43.04 kJ`
The emf of the cell `Zn|ZnCl_(2)` (0.05M) | AgCl(s)`,Ag is 1.015 V at 298 K and the temperature coefficient of its emf is `-4.92 xx 10^(-4)` V/K. How many of the reaction thermodynamic parameter `DeltaG`, `DeltaS` and `DeltaH` are negative at 298 K?A. None of themB. One of themC. Two of themD. All of them
The Gibbs energy for the decomposition of `Al_(2)O_(3)` at `500^(@)C` is as follow : `(2)/(3)Al_(2)O_(3) rarr (4)/(3)Al+O_(2), Delta_(r)G= +960 kJ mol^(-1)` The potential difference needed for the electrolytic reduction of aluminium oxide `(Al_(2)O_(3))` at `500^(@)C` isA. 4.5 VB. 3.0 VC. 2.5 VD. 5.0 V
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe(2+) lt Al`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
For the electrolytic production of `NaClO_(4)` from `NaClO_(3)` as per the following equation: `NaClO_(3) + H_(2)O rightarrow NaClO_(4) + H_(2)` How many faradays of electricity will be required to produce 0.5 "mole" of `NaClO_(4)` assuming 60% efficiency?A. 0.835 FB. 1.67 FC. 3.34 FD. 1.6 F
What must be concentration of `Ag^(+)` in an aqueous solution containing `Cu^(2+) =1.0 M` so that bot the metals can be deposited on the cathode simultaneously. Given that `E_(Cu//Cu^(2+))^(0)=-0.34V` and `E_(Ag^(+)//Ag)^(0)=0.812V,T=298K`A. Nearly `10^(-19)` MB. `10^(-12)` MC. `10^(-8)` MD. Nearly `10^(-16)` M
Which process occurs in the electrolysis of an aqueous tin (II) chloride solution at a tin anode?A. Sn = `Sn^(2+) + 2e^(-)`B. `2Cl^(-) = Cl_(2) + 2e^(-)`C. `2H_(2)O = O_(2) + 4H^(+) + 4e^(-)`D. None of these
How many electrons flow when a current of 5 amperes is passed through a conductor for 200 seconds?A. `6.241 xx 10^(21)`B. `6.0241 xx 10^(21)`C. `6.241 xx 10^(22)`D. `6.0241 xx 10^(20)`
The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)A. `3.74 xx 10^(20)`B. `6.0 xx 10^(23)`C. `7.48 xx 10^(21)`D. `6.0 xx 10^(20)`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment