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A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.(a) -55.1(b) 55.1(c) 66.1(d) -66.1I had been asked this question during an interview for a job.Question is taken from Resistance and Inductance in Series in portion Single Phase Series Circuits of Basic Electrical Engineering

Answer» RIGHT CHOICE is (a) -55.1

Explanation: φ=tan^-1(XL/R)=55.1

Since this is an INDUCTIVE circuit, the CURRENT will lag, hence φ= -55.1.


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