A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the voltage across the inductor.(a) 52V(b) 82V(c) 65V(d) 76VThe question was posed to me in exam.I would like to ask this question from Resistance and Inductance in Series topic in division Single Phase Series Circuits of Basic Electrical Engineering

A resistance of 7 ohm is connected in series with an inductance of 31.

1.	A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the voltage across the inductor.(a) 52V(b) 82V(c) 65V(d) 76VThe question was posed to me in exam.I would like to ask this question from Resistance and Inductance in Series topic in division Single Phase Series Circuits of Basic Electrical Engineering
Answer» Correct option is (B) 82V The best explanation: XL=2πFL = 10 OHM. Z^2=(R^2+XL^2) Therefore, the total impedance Z = 12.2ohm. V=IZ, therefore I=V/Z=100/12.2 = 8.2A.Voltage across INDUCTOR = 8.210 = 82V.

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