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A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the voltage across the inductor.(a) 52V(b) 82V(c) 65V(d) 76V |
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Answer» Correct option is (b) 82V The best explanation: XL=2*π*f*L = 10 ohm. Z^2=(R^2+XL^2) Therefore, the total impedance Z = 12.2ohm. V=IZ, therefore I=V/Z=100/12.2 = 8.2A. Voltage across inductor = 8.2*10 = 82V. |
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