1.

A resistance of `900Omega` is connected in series with a galvanometer of resistance `100Omega`. A potential difference of 1 Volt produces 100 division deflection in galvanometer. Find the figure of merit of galvanometer.

Answer» Correct Answer - `10^-5A//div`
Figure of merits, `K=1/theta=(V)/(Rtheta)=(1)/((900+100)100)`
`=10^-5A//d iv`.


Discussion

No Comment Found

Related InterviewSolutions