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A resistor of `5 Omega` is connected in series with a parallel combination of a number of resistors each of `5 Omega`. If the total resistance of the combination is `6 Omega` , how many resistor are in parallel? |
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Answer» Let n resistance each of `5 Omega` be connected in parallel. Their effective resistance is `1/R_(p) =1/5 + 1/5 +1/5 + .. N times =n/5 or R_(p)=5/n` As this parallel combination of resistance is connected in series with `5 Omega` resistance, the total resistance of the combination is `R=R_(p) + 5 = (5/n)+5 or 5/6 = 6-5=1` or `n=5` |
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