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A resistor of `6kOmega`with tolerance 10% and another resistance of `4kOmega` with tolerance `10%` are connected in series. The tolerance of the combination is aboutA. 0.05B. 0.1C. 0.12D. 0.15

Answer» Correct Answer - B
In series combination,
`R = R_(1)+R_(2)=6+4=10 k Omega`
Error in combination,
`Delta R = Delta R_(1)+Delta R_(2)`
`= (10)/(100)xx6+(10)/(100)xx4`
`= 0.6+0.4=1`
`(Delta R)/(R )=(1)/(10)=10%`


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