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A resistor of `6kOmega`with tolerance 10% and another resistance of `4kOmega` with tolerance `10%` are connected in series. The tolerance of the combination is aboutA. 0.05B. 0.1C. 0.12D. 0.15 |
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Answer» Correct Answer - B In series combination, `R = R_(1)+R_(2)=6+4=10 k Omega` Error in combination, `Delta R = Delta R_(1)+Delta R_(2)` `= (10)/(100)xx6+(10)/(100)xx4` `= 0.6+0.4=1` `(Delta R)/(R )=(1)/(10)=10%` |
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