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A resonance tube is resonated with tuning fork of frequency 512 Hz. Two successive lengths of the resonated air-column are 16.0 cm and 51.0 cm. The experiment is performed at the room temperature of 40^(@)C calculate the speed of sound at 0^(@)Cand the end correction. |
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Answer» Solution :Here `V=512Hz, L_(1)=16.0cm=0.16m, L_(2)=51.0cm=0.51m` SPEED of SOUND at `40^(@)C`, `v=2V(L_(2)-L_(1))` `=2xx512xx(0.51-0.16)` `=358.4ms^(-1)` Speed of sound at `0^(@)C` is given by `v_(o)=v-0.61t=358.4-0.61xx40` `=350.4-24.4-334ms^(-1)` End correction `=(L_(2)-3L_(1))/(2)=(51.0-48.0)/(2)` =1.5cm. |
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