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A resonance tube is resonated with tuning fork of frequency 512 Hz. Two successive lengths of the resonated air-column are 16.0 cm and 51.0 cm. The experiment is performed at the room temperature of 40^(@)C calculate the speed of sound at 0^(@)Cand the end correction. |
Answer» <html><body><p></p>Solution :Here `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>=512Hz, L_(1)=16.0cm=0.16m, L_(2)=51.0cm=0.51m` <br/> <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of <a href="https://interviewquestions.tuteehub.com/tag/sound-648690" style="font-weight:bold;" target="_blank" title="Click to know more about SOUND">SOUND</a> at `<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>^(@)C`, <br/> `v=2V(L_(2)-L_(1))` <br/> `=2xx512xx(0.51-0.16)` <br/> `=358.4ms^(-1)` <br/> Speed of sound at `0^(@)C` is given by <br/> `v_(o)=v-0.61t=358.4-0.61xx40` <br/> `=350.4-24.4-334ms^(-1)` <br/> End correction <br/> `=(L_(2)-3L_(1))/(2)=(51.0-48.0)/(2)` <br/> =1.5cm.</body></html> | |