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A right angled triangular prism of refractive index `mu_(1)` is kept floating on a liquid (surface) having refractive index `mu_(2)`. The condition such tat light incident normally passes through base of prism as shown in figure.A. `mu_(1)=Cos2theta//Costheta`B. `mu_(2)=Cos2theta//Costheta`C. `mu_(1)=Sin2theta//Costheta`D. `mu_(2)=Sin2theta//Sintheta` |
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Answer» Correct Answer - B `sin(90-theta)=(1)/(mu_(1))impliescostheta=(1)/(mu_(1))to(1)` `sin(90-2theta)=(1)/((mu_(1)//mu_(2)))` `cos2theta=(mu_(2))/(mu_(1))=(mu_(2))/((1//costheta))thereforemu_(2)=(cos2theta)/(costheta)` |
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