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A right pyramid is on a regular hexagonal base. Each side of the base is 10 m and its height is 30 m. Find the volume of the pyramid ? |
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Answer» Volume of a pyramid = \(\frac{1}{3}\) × (Area of the base) × Height = \(\frac{1}{3} \times \frac{3\sqrt{3}}{2} \times (5)^2 \times 30 \) = 649.52 m3 ≈ 650m3 (Area of a regular hexagon of side 'a' = \(\frac{3\sqrt{3}}{2} a^2\) ) |
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