A ring having a cross-sectional area of 500 mm^2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Relative permeability of ring is 380. Calculate the reluctance.(a) 1.68 * 10^-4A/Wb(b) 1.68 * 10^4 A/Wb(c) 1.68 * 10^6 A/Wb(d) 1.68 * 10^-6A/WbThe question was posed to me in quiz.My query is from Ohm’s Law for a Magnetic Circuit topic in chapter Simple Magnetic Circuits of Basic Electrical Engineering

A ring having a cross-sectional area of 500 mm^2, a circumference of 4

1.	A ring having a cross-sectional area of 500 mm^2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Relative permeability of ring is 380. Calculate the reluctance.(a) 1.68 * 10^-4A/Wb(b) 1.68 * 10^4 A/Wb(c) 1.68 * 10^6 A/Wb(d) 1.68 * 10^-6A/WbThe question was posed to me in quiz.My query is from Ohm’s Law for a Magnetic Circuit topic in chapter Simple Magnetic Circuits of Basic Electrical Engineering
Answer» Right option is (c) 1.68 * 10^6 A/Wb To EXPLAIN I WOULD say: Reluctance=l/(µA) = l/(µrµ0A) SUBSTITUTING the VALUES, we GET Reluctance=1.68*10^6 A/Wb.

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