1.

A ring having a cross-sectional area of 500 mm^2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Relative permeability of ring is 380. Calculate the magnetising current.(a) 6.7A(b) 7.7A(c) 7.6(d) 6.1AThe question was asked in a job interview.This key question is from Ohm’s Law for a Magnetic Circuit topic in section Simple Magnetic Circuits of Basic Electrical Engineering

Answer»

Right choice is (a) 6.7A

For EXPLANATION: Reluctance = l/(µ*A) = l/(µrµ0*A)

SUBSTITUTING the VALUES, we get Reluctance S=1.68*106 A/Wb.

F=ϕSSubstituting the given values, we get F = 1344At.

I=F/NSubstituting the values from the question, we get I=6.7A.



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