A ring having a cross-sectional area of 500 mm^2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the flux density of the ring.(a) 1.6T(b) 2.6T(c) 3.6T(d) 4.6TThe question was asked in a national level competition.Origin of the question is Ohm’s Law for a Magnetic Circuit topic in chapter Simple Magnetic Circuits of Basic Electrical Engineering

A ring having a cross-sectional area of 500 mm^2, a circumference of 4

1.	A ring having a cross-sectional area of 500 mm^2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the flux density of the ring.(a) 1.6T(b) 2.6T(c) 3.6T(d) 4.6TThe question was asked in a national level competition.Origin of the question is Ohm’s Law for a Magnetic Circuit topic in chapter Simple Magnetic Circuits of Basic Electrical Engineering
Answer» RIGHT answer is (a) 1.6T Explanation: ϕ=BA => Flux DENSITY B = ϕ/A Substituting the VALUES, we get B=1.6T.

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