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A ring is made of a wire having a resistance `R_(0) = 12 Omega`. Find the point `A` and `B`, as shown in the figure, at which a current carrying conductor should be connected so that the resistance `R` of the subcircuit between these points is equal to `(8)/(3) Omega` A. `(l_(1))/(l_(2)) = (1)/(2)`B. `(l_(1))/(l_(2)) = (5)/(8)`C. `(l_(1))/(l_(2)) = (1)/(3)`D. `(l_(1))/(l_(2)) = (3)/(8)` |
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Answer» Correct Answer - A (a) `((A)/(rho l_(1)) + (A)/(rho l_(2))) = (3)/(8)` `(rho (l_(2) + l_(2)))/(A) = 12` Solving `(l_(1))/(l_(2)) = (1)/(2)` |
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