1.

A ring mass `m` and radius `R` has three particle attached to the ring as shown in the figure. The centre of the centre `v_(0)`. Find the kinetic energy of the system. (Slipping is absent). .

Answer» Correct Answer - `6mv_(0)^(2)`
About instantaneous axis of rotation rolling system can be considered as pure rotation
`KE = (1)/(2) I omega^(2)` …(1)
here `I` = moment of inertia about instantaneous axis of rotation
`I = 2m (sqrt(2) R)^(2) + m(2R)^(2) + m(sqrt(2) R)^(2) + I_(ring)`
`I = 2m (sqrt(2) R)^(2) + m(2R)^(2) + m(sqrt(2) R)^(2) + mR^(2)`
`I = 12 mR^(2)`
putting the value of `I` in equation (1)
`KE = 6mR^(2) omega^(2)`
`KE = 6m(R omega)^(2)`
`KE = 6mv_(o)^(2)`.


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