A ring of mass M and R is rotating about its axis with angular velocity omega. Two identical bodies each o mass m are now gently attached at the two ends of a diameter of the ring. Because of this the kinetic energy loss will be :

A ring of mass M and R is rotating about its axis with angular velocit

1.	A ring of mass M and R is rotating about its axis with angular velocity omega. Two identical bodies each o mass m are now gently attached at the two ends of a diameter of the ring. Because of this the kinetic energy loss will be :
Answer» `(m(M+2m))/(M)OMEGA^(2)R^(2)` `(MM)/((M+m))omega^(2)R^(2)` `(Mm)/((M+2m))omega^(2)R^(2)` `((M+m)M)/((M+2m))omega^(2)R^(2)` Answer :C