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A ring of mass `M` and radius `R` is released on an inclined as shown. If the coefficient of friction `mu lt 1/2 tan theta`, then during a displacement `l`: A. Acceleration of the ring `=g//2sintheta`B. Acceleration of the ring `=g sin theta-mug costheta`C. work done by the force of friction `=mgl(sintheta-ucostheta)`D. work done by the force of friction is zero |
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Answer» Correct Answer - B |
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