A ring of mass M and radius R is rotating about its axis with angular velocity omega. Two dentical bodies each o mass m are now gently attached at the two ends of a diameter of the ring. Because of this, the kinetic energy loss will be:

A ring of mass M and radius R is rotating about its axis with angular

1.	A ring of mass M and radius R is rotating about its axis with angular velocity omega. Two dentical bodies each o mass m are now gently attached at the two ends of a diameter of the ring. Because of this, the kinetic energy loss will be:
Answer» `(m(M+2m))/(M) omega^(2)R^(2)` `(MM)/((M+m))omega^(2)R^(2)` `(Mm)/((M+2m))omega^(2)R^(2)` `((M+m)M)/(M+2m)omega^(2)R^(2)` ANSWER :C