A ring of mass M is rolling down an inclined plane . The length of this plane is L . It makes an angle theta with the horizontal . Find the velocity of the centre of mass of the ring at the centre of the plane.

A ring of mass M is rolling down an inclined plane . The length of thi

1.	A ring of mass M is rolling down an inclined plane . The length of this plane is L . It makes an angle theta with the horizontal . Find the velocity of the centre of mass of the ring at the centre of the plane.
Answer» SOLUTION :The velocity of a body rolling down an inclined plane , `v = sqrt((2 g S SIN theta)/(1 + (K^(2))/(R^2)))` For ring `K= R , S = (L)/(2)` . `therefore v = sqrt((2 g xx (L)/(2) xx sin theta)/(1 + l)) = sqrt((gL sin theta)/(2))`