1.

A ring of radius 0.5 m and mass 10 kg is rotating about its diameter with angular velocity of 20 rad s^(-1). Its kinetic energy is

Answer»

10 J
100 J
500 J
250 J

Solution :MOMENT of inertia of a ring about its diameter `I = (1)/(2)MR^(2)` and kinetic energy is GIVEN by
`E_(k)=(1)/(2)I omega^(2)rArr E_(k)=(1)/(4)mr^(2)omega^(2)=(1)/(4)xx10xx(0.5)^(2)xx(20)^(2)=250 J`.


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