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A ring of resistance `10Omega`, radius `10 cm` and `100` turns is rotated at a rate revolutions per second about its diameter is perpendicular to a uniform magnetic field of induction `10 mT`. The amplitude of the current in the loop will be nearly `("Take": pi^(2)=10)`A. `200A`B. `2A`C. `0.002A`D. none of these |
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Answer» Correct Answer - B `phi=NAB cos omegat` `e=NBAomega sinomegat` `e_(0)=NBAomega` `I_(0)=(NBAomega)/R` `=(100xx10^(-2)xxpixx(.1)^(2)2pixx100)/10=2A` |
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