 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | A river `10 m` deep is flowing at `5ms^(-1)`. The shearing stress between horizontal layers of the rivers is (`eta=10^-(3) SI` units)A. `10^(-3)N//m^(2)`B. `0.8xx10^(-3)N//m^(2)`C. `0.5xx10^(-3)N//m^(2)`D. `1 N//m^(2)` | 
| Answer» Correct Answer - C Shearing stress`=(|"viscous force"|)/("area")` `=(etaA(dv)/(dx))/A=eta(dv)/(dx)` `10^(-3)xx5/10N/m^(2)=05.5xx10^(-3)N//m^(2)` | |